Return-Path: Received: (qmail 13056 invoked from network); 29 Aug 1999 06:25:37 -0000 Received: from magnus.plus.net.uk (HELO magnus.force9.net) (195.166.128.27) by murphys.force9.net with SMTP; 29 Aug 1999 06:25:37 -0000 Received: (qmail 13757 invoked from network); 29 Aug 1999 06:23:34 -0000 Received: from unknown (HELO post.thorcom.com) (212.172.148.70) by magnus.plus.net.uk with SMTP; 29 Aug 1999 06:23:34 -0000 Received: from majordom by post.thorcom.com with local (Exim 3.02 #1) id 11KyFZ-0004GQ-00 for rsgb_lf_group-outgoing@blacksheep.org; Sun, 29 Aug 1999 07:15:33 +0100 X-Priority: 3 X-MSMail-Priority: Normal Received: from ah-img-4.compuserve.com ([149.174.217.158] helo=hpamgaad.compuserve.com ident=mailgate) by post.thorcom.com with esmtp (Exim 3.02 #1) id 11KyFX-0004GL-00 for rsgb_lf_group@blacksheep.org; Sun, 29 Aug 1999 07:15:32 +0100 Received: (from mailgate@localhost) by hpamgaad.compuserve.com (8.8.8/8.8.8/HP-1.8) id CAA04556 for rsgb_lf_group@blacksheep.org; Sun, 29 Aug 1999 02:15:29 -0400 (EDT) X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 Date: Sun, 29 Aug 1999 02:15:20 -0400 From: "Dave Sergeant" Subject: LF: Loops - current measurements To: "rsgb_lf_group" Message-ID: <199908290215_MC2-82C5-1427@compuserve.com> MIME-Version: 1.0 Content-Transfer-Encoding: 8bit Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Disposition: inline Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Sender: >From Dave G3YMC This is a follow up on the mails earlier this month on this subject. Today, assisted by Steve GW4ALG, we measured the rf current in my transmit loop in a similar fashion to Steve's measurements on his loop. For details of my loop see my web site: http://ourworld.compuserve.com/homepages/sergeantd/136.htm I have previously done extensive simulation of my loop and its matching network using a circuit analysis package and from the required values of capacitors in the network to achieve correct match concluded that the effective resistance of my loop at 136 is around 0.6ohms. Measurements are as follows: DC resistance 0.1ohms Wire: twin 79/0.2mm loudspeaker cable, the two pairs joined in parallel Measured input power 5.2W Loop Current 2.64A DC resistance of RF meter 0.09 ohm hence Loop resistance 0.66 ohm (R=P/(I*I) This result fits exactly with my previous simulations! Note that at my normal transmit power of 35W the loop current is 8 A and if I were to put 400W into it I would get 26 A - perhaps the caps would start objecting! At first I thought much of this loss was due to the series loss resistance of the matching capacitors (Philips 376) but further calculations from the datasheets shows this not to be the case, as this is only around 50 milliohms. What I need is an accurate formula for calculating the skin effect resistance of the wire. The 98 ARRL handbook has a 'rough guide' formula which would increase the resistance by a factor of around 3.5, which is not enough, unless there is another effect I have overlooked. As an aside, for those of you who remember the Cross Field Antenna discussion on here a few months back, GM3HAT now has a paper describing the CFA antennas in Egypt (http://www.antennex.com/preview/cfa/nab99cfa.htm) which makes interesting, if amusing reading. It sounds convincing until you start asking yourself how the beasty really works and what it doesn't say... Enough said. Cheers Dave G3YMC sergeantd@compuserve.com