Return-Path: Received: (qmail 6630 invoked from network); 28 Nov 2002 08:39:05 -0000 Received: from murphys.services.quay.plus.net (212.159.14.225) by mailstore with SMTP; 28 Nov 2002 08:39:05 -0000 Content-Transfer-Encoding: 8bit Received: (qmail 890 invoked from network); 28 Nov 2002 08:38:53 -0000 X-Priority: 3 X-MSMail-Priority: Normal Received: from post.thorcom.com (193.82.116.70) by murphys.services.quay.plus.net with SMTP; 28 Nov 2002 08:38:53 -0000 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 X-SQ: A Received: from majordom by post.thorcom.com with local (Exim 4.10) id 18HKBl-0006d4-00 for rsgb_lf_group-outgoing@blacksheep.org; Thu, 28 Nov 2002 08:38:25 +0000 Received: from [134.58.10.57] (helo=mail3.cc.kuleuven.ac.be) by post.thorcom.com with esmtp (Exim 4.10) id 18HKBk-0006cu-00 for rsgb_lf_group@blacksheep.org; Thu, 28 Nov 2002 08:38:24 +0000 Received: from dell-rik.fys.kuleuven.ac.be (pc-10-33-165-177.fys.kuleuven.ac.be [10.33.165.177]) by mail3.cc.kuleuven.ac.be (8.12.1/8.12.1) with ESMTP id gAS8bsJT042158 for ; Thu, 28 Nov 2002 09:37:54 +0100 Message-ID: <5.1.0.14.0.20021128091551.02d6a100@pb623250.kuleuven.be> X-Sender: pb623250@pb623250.kuleuven.be X-Mailer: QUALCOMM Windows Eudora Version 5.1 Date: Thu, 28 Nov 2002 09:44:24 +0100 To: rsgb_lf_group@blacksheep.org From: "Rik Strobbe" In-reply-to: <3DE5B958.5738.32FCF@localhost> References: <5.1.0.14.0.20021125171906.00b9d028@pb623250.kuleuven.be> <001d01c29475$f77f6140$0500a8c0@charter.net> MIME-Version: 1.0 Subject: Re: LF: loop antenna Content-Type: text/plain; charset=us-ascii; format=flowed X-Spam-Status: No, hits=-0.5 required=5.0tests=IN_REP_TO,REFERENCES,SPAM_PHRASE_00_01version=2.42 Sender: Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Hello group, many thanks to all who replied on my request. One more thought : if the loop would be very good (= low loss, let's say about 0.5 Ohm) this would mean high current and thus also rather high voltage (as Jim mentioned). The loop would have an inductance of about 120uH (thus XL = 100 Ohm), so pumping 450W into the loop would give a current of 30A and a voltage of 3kV. Isn't it likely that these high voltages will cause some additional losses (there will be some current floating to ground) ? 73, Rik ON7YD