Return-Path: Received: from post.thorcom.com (post.thorcom.com [195.171.43.25]) by mtain-dh05.r1000.mx.aol.com (Internet Inbound) with ESMTP id 9303E3800008B; Tue, 24 Jul 2012 22:29:40 -0400 (EDT) Received: from majordom by post.thorcom.com with local (Exim 4.14) id 1StrKk-00063B-VY for rs_out_1@blacksheep.org; Wed, 25 Jul 2012 03:28:18 +0100 Received: from [195.171.43.32] (helo=relay1.thorcom.net) by post.thorcom.com with esmtp (Exim 4.14) id 1StrKk-000632-AI for rsgb_lf_group@blacksheep.org; Wed, 25 Jul 2012 03:28:18 +0100 Received: from nm2-vm0.bullet.mail.ird.yahoo.com ([77.238.189.199]) by relay1.thorcom.net with smtp (Exim 4.77) (envelope-from ) id 1StrKi-0002UG-F9 for rsgb_lf_group@blacksheep.org; Wed, 25 Jul 2012 03:28:17 +0100 Received: from [77.238.189.52] by nm2.bullet.mail.ird.yahoo.com with NNFMP; 25 Jul 2012 02:28:15 -0000 Received: from [212.82.108.225] by tm5.bullet.mail.ird.yahoo.com with NNFMP; 25 Jul 2012 02:28:15 -0000 Received: from [127.0.0.1] by omp1002.bt.mail.ird.yahoo.com with NNFMP; 25 Jul 2012 02:28:15 -0000 X-DKIM-Result: Domain=btopenworld.com Result=Signature OK X-Yahoo-Newman-Id: 453561.15090.bm@omp1002.bt.mail.ird.yahoo.com Received: (qmail 20196 invoked from network); 25 Jul 2012 02:28:15 -0000 DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=s1024; d=btopenworld.com; h=DKIM-Signature:X-Yahoo-Newman-Property:X-YMail-OSG:X-Yahoo-SMTP:Received:Message-ID:From:To:References:In-Reply-To:Subject:Date:MIME-Version:Content-Type:Content-Transfer-Encoding:X-Priority:X-MSMail-Priority:X-Mailer:X-MimeOLE; b=r2pGl8ODgOzYjdvqoVkaMyNyP6PwOjEbfT6eQp0wjDf4ucdb5/cWuM/76Ob1iOBKUeenGsxJ1SkIQJT4OEZW3THKNTIr7IyqSUWaFgEk2IMw6mIJognjU9kDO6/U3eSMmBumvQhRswLdeNR3/ASlZPsyig7NZ0UESAwxNnwqrjA= ; DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=btopenworld.com; s=s1024; t=1343183295; bh=fgpvUDVYXTroj2LnedzVQsbkDiZxx1WM6wq1NAeejG8=; h=X-Yahoo-Newman-Property:X-YMail-OSG:X-Yahoo-SMTP:Received:Message-ID:From:To:References:In-Reply-To:Subject:Date:MIME-Version:Content-Type:Content-Transfer-Encoding:X-Priority:X-MSMail-Priority:X-Mailer:X-MimeOLE; b=LovkdJdqcbqmCMcUZaFr1G4DL07QdCiIm5NtIX3abwRgDO4x5+LnEg8fuBfgWSglJX/Un/slbVxrKmy4T5H5esE2gty4yUHsDT6uS5lAl4SOq+xDXQ+usxYXmm2HpntWT9loYhdCUnDgMUOk8loX9IN6xhc8xO3pLpEv3SFA++M= X-Yahoo-Newman-Property: ymail-3 X-YMail-OSG: Av4s0eoVM1laFHTW8nyb55rXsyx_FfYupfPelaHgiUu7hYf tC.iVoEYl5V0npqeYWD4F1tklToT3N6T1Usk2kAPRc8BfcvDdui9xxYhc7Ut A3Bx5tJGY1JU72QtRj2fQj.YHjx7uXvjIfS2rf7V.rGW4K2xKKoArf9KLr9w EjTI3TDZP_YViBWevuQ.NdOyy5D1yn.ZzUPEStMG.OpshqsMJwJP7bPJ8VZZ qCWm3BVan8sA5vj5tVE1W84G3ZSxeXKvsv0LcSMCQ9WByc7JjZm4cs97M3HR PFdZp9dG8zkQhzt_nK9vm9OUAk0VgtXprA0PjONAT8lkwozILKKBx_cV3mUr 1scVS1Eb4y8C_.QnQOTfAYyc2FJqgcLAHlwL3nlW0sy4AYUn3Sxs5.cXOHBz ANTguKR59i4X3ISPd0Z.rhOuHPfH2niEEDDGH9DG3yaeR_liF X-Yahoo-SMTP: Cxhli3eswBD1ozmtAojhjrja86kWx0Qm9tycD5QR1DKWrOLgjJcXkw-- Received: from JimPC (james.moritz@86.185.202.35 with login) by smtp826.mail.ukl.yahoo.com with SMTP; 24 Jul 2012 19:28:15 -0700 PDT Message-ID: <3E9653200305422E8F12BCF9447F314F@JimPC> From: "James Moritz" To: References: <500EB973.8080005@iup.uni-heidelberg.de> In-Reply-To: <500EB973.8080005@iup.uni-heidelberg.de> Date: Wed, 25 Jul 2012 03:28:16 +0100 MIME-Version: 1.0 X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Windows Mail 6.0.6002.18197 X-MimeOLE: Produced By Microsoft MimeOLE V6.0.6002.18463 X-Spam-Score: 0.0 (/) X-Spam-Report: Spam detection software, running on the system "relay1.thorcom.net", has identified this incoming email as possible spam. The original message has been attached to this so you can view it (if it isn't spam) or label similar future email. If you have any questions, see the administrator of that system for details. Content preview: Dear Stefan, LF Group, ...> there will be a real component of > Z=R (=resonance)of 46 Ohm. So i would not even need a transformer to match > the antenna to the PA. ...However, if you wish the antenna to operate in a "dipole" mode, you will need some way of making sure that the currents into the 2 terminals of the feed point are equal - otherwise, you will have 2 asymmetrical inverted-L vertical antennas back-to-back! You could achieve nearly equal currents by ensuring all the system, TX, power supply, etc., was "floating" and completely insulated from ground, but the resulting unpredictable RF voltage between the equipment and the actual ground might be a problem. So a well-insulated transformer would probably be a necessity, even if not required for matching. [...] Content analysis details: (0.0 points, 5.0 required) pts rule name description ---- ---------------------- -------------------------------------------------- -0.0 RCVD_IN_DNSWL_NONE RBL: Sender listed at http://www.dnswl.org/, no trust [77.238.189.199 listed in list.dnswl.org] 0.0 T_DKIM_INVALID DKIM-Signature header exists but is not valid 0.0 UNPARSEABLE_RELAY Informational: message has unparseable relay lines X-Scan-Signature: e6de17d69e46ff4ea8db042ef2cd7e46 Subject: LF: Re: Pretests for the 630m band dipole Content-Type: text/plain; format=flowed; charset="ISO-8859-15"; reply-type=response Content-Transfer-Encoding: 7bit X-Spam-Checker-Version: SpamAssassin 2.63 (2004-01-11) on post.thorcom.com X-Spam-Level: X-Spam-Status: No, hits=0.1 required=5.0 tests=MISSING_OUTLOOK_NAME autolearn=no version=2.63 X-SA-Exim-Scanned: Yes Sender: owner-rsgb_lf_group@blacksheep.org Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group X-SA-Exim-Rcpt-To: rs_out_1@blacksheep.org X-SA-Exim-Scanned: No; SAEximRunCond expanded to false x-aol-global-disposition: G X-AOL-SCOLL-SCORE: 0:2:444504480:93952408 X-AOL-SCOLL-URL_COUNT: 0 X-AOL-SCOLL-AUTHENTICATION: mail_rly_antispam_dkim-m218.1 ; domain : btopenworld.com DKIM : fail x-aol-sid: 3039ac1d4119500f5a137e88 X-AOL-IP: 195.171.43.25 X-AOL-SPF: domain : blacksheep.org SPF : none Dear Stefan, LF Group, ...> there will be a real component of > Z=R (=resonance)of 46 Ohm. So i would not even need a transformer to match > the antenna to the PA. ...However, if you wish the antenna to operate in a "dipole" mode, you will need some way of making sure that the currents into the 2 terminals of the feed point are equal - otherwise, you will have 2 asymmetrical inverted-L vertical antennas back-to-back! You could achieve nearly equal currents by ensuring all the system, TX, power supply, etc., was "floating" and completely insulated from ground, but the resulting unpredictable RF voltage between the equipment and the actual ground might be a problem. So a well-insulated transformer would probably be a necessity, even if not required for matching. > 85% means that one wire is "just" 47m. So if someone lives close to a > forest, there would be a chance to build such a TX antenna and run the > major part of the antenna outside the garden. Just a short rest has to be > inside the own property. For a 90% feed, R would be 96 Ohm. This could be > matched to 50 Ohm very easily and the shorter part of the antenna would > only be 31.5m... I am sceptical about how this will actually work in practice. The short section of the asymmetrical dipole on its own will no doubt behave as a normal inverted-L antenna, and will have of the order of a kilohm of capacitive reactance, measured between its terminal and a ground connection. In order to end up with a resistive overal feed point impedance, the longer section will have to have a corresponding large inductive reactance. These reactances will be quite large compared to the resistive components - intuitively, I have my doubts about whether a long piece of wire trailing through the forest will behave as a fairly high-Q inductor... The concept must fail at some point, e.g. what happens when you have only 1m of wire in the short section of the dipole? Having used NEC antenna simulators in the past, I am not at all sure that they handle the effect of a lossy ground very accurately. Cheers, Jim Moritz 73 de M0BMU