Return-Path: Received: (qmail 24889 invoked from network); 17 Dec 1999 16:34:19 -0000 Received: from unknown (HELO post.thorcom.com) (212.172.148.70) by teachers.core.plus.net.uk with SMTP; 17 Dec 1999 16:34:19 -0000 Received: from majordom by post.thorcom.com with local (Exim 3.02 #1) id 11z0ht-0004Es-00 for rsgb_lf_group-outgoing@blacksheep.org; Fri, 17 Dec 1999 16:58:17 +0000 Content-Transfer-Encoding: 8bit Received: from mail.cc.kuleuven.ac.be ([134.58.10.6]) by post.thorcom.com with esmtp (Exim 3.02 #1) id 11z0hs-0004En-00 for rsgb_lf_group@blacksheep.org; Fri, 17 Dec 1999 16:58:16 +0000 X-Priority: 3 Received: from LCBD15.fys.kuleuven.ac.be (LCBD15.fys.kuleuven.ac.be [134.58.80.15]) by mail.cc.kuleuven.ac.be (8.9.3/8.9.0) with SMTP id RAA98868 for ; Fri, 17 Dec 1999 17:26:02 +0100 X-MSMail-Priority: Normal Message-ID: <3.0.1.16.19991217182454.2eefc442@mail.cc.kuleuven.ac.be> X-Sender: pb623250@mail.cc.kuleuven.ac.be X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 X-Mailer: Windows Eudora Pro Version 3.0.1 (16) Date: Fri, 17 Dec 1999 18:24:54 To: rsgb_lf_group@blacksheep.org From: "Rik Strobbe" Subject: Re: LF: Re.LF 162Khz field strength. In-reply-to: <000201bf48a2$64189e20$5f2d893e@lvm> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii; format=flowed Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Sender: At 15:19 17/12/99 -0000, you wrote: >Relating all this to the possibility of transatlantic QSOs it seems that there >will be no ground wave so we are only concerned with the reflected wave and >therefore the height of the ref.layer,but at only 60-80Kms the number of hops >will be very great and thus the distance the waves have to travel! >can anybody do the spherical geometry to work this out? As far as I remind my maths the 'skip distance' should be : D = 2 x 111 x arccos( R/(R+H)) Where D = skip distance (km), R = earth radius (6366km), H = layer height (in km). For a height of 60km the skip distance would be 1724km, for a height of 80km it would be 1988km. But the above assumes that the take-off angle is 0 degrees. Since vertical polarized signals at this frequency tend to 'bend' arround the earth (groundwave) they might not (or very little) escape into the 'sky'. If you have higher radiation angles then the skip distance becomes considerably shorter. 73, Rik ON7YD