Return-Path: Received: from mtain-dc12.r1000.mx.aol.com (mtain-dc12.r1000.mx.aol.com [172.29.64.140]) by air-dd08.mail.aol.com (v127_r1.1) with ESMTP id MAILINDD081-860e4b8647f532e; Thu, 25 Feb 2010 04:50:45 -0500 Received: from post.thorcom.com (post.thorcom.com [193.82.116.20]) by mtain-dc12.r1000.mx.aol.com (Internet Inbound) with ESMTP id 758A238000043; Thu, 25 Feb 2010 04:50:43 -0500 (EST) Received: from majordom by post.thorcom.com with local (Exim 4.14) id 1NkaL8-0001HE-G1 for rs_out_1@blacksheep.org; Thu, 25 Feb 2010 09:49:02 +0000 Received: from [193.82.116.32] (helo=relay1.thorcom.net) by post.thorcom.com with esmtp (Exim 4.14) id 1NkaL7-0001H5-U5 for rsgb_lf_group@blacksheep.org; Thu, 25 Feb 2010 09:49:01 +0000 Received: from cavuit02.kulnet.kuleuven.be ([134.58.240.44]) by relay1.thorcom.net with esmtp (Exim 4.63) (envelope-from ) id 1NkaL5-0002Y7-16 for rsgb_lf_group@blacksheep.org; Thu, 25 Feb 2010 09:49:01 +0000 Received: from smtps01.kuleuven.be (smtpshost01.kulnet.kuleuven.be [134.58.240.74]) by cavuit02.kulnet.kuleuven.be (Postfix) with ESMTP id 01AFA51C002 for ; Thu, 25 Feb 2010 10:48:47 +0100 (CET) Received: from PC_van_Rik.fys.kuleuven.be (dhcp-10-33-85-106.fys.kuleuven.be [10.33.85.106]) by smtps01.kuleuven.be (Postfix) with ESMTP id EA85531E702 for ; Thu, 25 Feb 2010 10:48:46 +0100 (CET) X-Mailer: QUALCOMM Windows Eudora Version 7.1.0.9 Date: Thu, 25 Feb 2010 10:48:47 +0100 To: "rsgb_lf_group@blacksheep.org" X-Kuleuven: This mail passed the K.U.Leuven mailcluster From: Rik Strobbe References: <001c01cab575$6bbb0460$0401a8c0@xphd97xgq27nyf> Mime-Version: 1.0 Message-Id: <20100225094846.EA85531E702@smtps01.kuleuven.be> X-KULeuven-Information: Katholieke Universiteit Leuven X-KULeuven-Scanned: Found to be clean X-KULeuven-Envelope-From: rik.strobbe@fys.kuleuven.be X-Spam-Score: 0.6 (/) X-Spam-Report: autolearn=disabled,HTML_00_10=0.642,HTML_MESSAGE=0.001 Subject: LF: 9kHz Content-Type: multipart/alternative; boundary="=====================_27043522==.ALT" X-Spam-Checker-Version: SpamAssassin 2.63 (2004-01-11) on post.thorcom.com X-Spam-Level: X-Spam-Status: No, hits=0.0 required=5.0 tests=HTML_MESSAGE, TO_ADDRESS_EQ_REAL autolearn=no version=2.63 X-SA-Exim-Scanned: Yes Sender: owner-rsgb_lf_group@blacksheep.org Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group X-SA-Exim-Rcpt-To: rs_out_1@blacksheep.org X-SA-Exim-Scanned: No; SAEximRunCond expanded to false x-aol-global-disposition: G x-aol-sid: 3039ac1d408c4b8647f31363 X-AOL-IP: 193.82.116.20 --=====================_27043522==.ALT Content-Type: text/plain; charset="us-ascii"; format=flowed Stefan, did you have a look at the graph Jim (M0BMU) showed yesterday ? This may indicate that in an open area you might be better off than 1/f, maybe in the 50..100 Ohm range. Last night I was mulling about Alexanders remark that a parallel C would increase the losses. At first though I would say that the parallel C just performs some kind of impedance transformation without inducing additional losses. And this is true if the loading coil would be perfect (no losses). But for a real world situation (ie. assuming a constant Q = 250 for the loading coil) Alexander is right: the transformation caused by a large parallel C causes extreme high currents in the loading coil, and thus higher losses. Simulation (with SIMetrix) confirms this. Taking your antenna (580pF / 50 Ohm) 1. Without parallel C you would need a 550mH loading coil. At Q = 250 the coil loss would be 130 Ohm. Putting 100W into this system would result in an antenna current of about 750mA and antenna voltage of 23kV. 750mA trough the loading coil means a dissipation of 73W. 2. With a 3.2nF parallel C you would need a 85mH loading coil. At Q = 250 the coil loss would be 20 Ohm. But putting 100W into this system would result in only 330mA antenna current, while the current through the loading coil would be 2.1A (= 88W dissipation). The reduction in antenna current (750mA to 330mA) would lower the ERP by 7dB. In addition the parallel C will decrease the antenna bandwidth significantly, making it difficult to tune. 73, Rik ON7YD - OR7T At 01:14 25/02/2010, you wrote: >Here i agree. And here i understand "dreamers" in a positive and >optimistic way, just like children are dreamers! >We have written so many mails (including me, of course ;-) ) und >could start now just to try what is possible to reach more than 10km >if not done yet. > >On the LF pages of DK8KW i found a notice of a successful 2 way QSO >over 10km @ <9kHz. Does anybody know about more than 10km by amateurs? > >Yesterday in the night i talked more than 1 hour to Markus/DF6NM and >he persuaded me to try it with the 100m vertical in a first test. >Maybe i get that temp licence for a 300m kite vertical but the >public autoritys are still discussing if i need a special casualty insurance... > >Do you, the group, think that it makes sense to try it if the next >listening station is >50km or even more away? What could be possible >if this would be the arrangement with the 100m vertical: > >The wire has abt 580pF >I can get a air coil with L=85mH out of a 20kV field. DC resistance >abt 150mOhm, continous current abt 30A, voltage over coil abt 30kV >rms (if it remains dry(!)), measured self resonance frequency abt 50kHz. >So, if f=8,9kHz, a parallel C of abt 3,2nF is needed (i can get some >470pF/40kV Cs, no problem) >The voltage across my thin wire should be limited to abt 20kV rms, >that means, antenna current should not exceed 650mA. >If Rik's 1/f dependency is valid, then my ground losses will be in >the region of 250 Ohm (no houses and trees there on the hill in a >radius of abt 100m; 15Ohm @ 137 kHz). >So, 100W TX power would radiate 1,4mW and thus the efficiency would >be 0,0014%. In that case, i mustn't apply more than 100W since the >voltage across the wire would be to high, so no need for a QRO PA... > >If that calculation is reasonably correct, what distance could be >reached with 1,4mW @ 8,9 kHz in e.g. QRSS10 and the noise level that >can be expected on a sunday morning? :-) > >73 es wish gl to all those, who are trying in these days ;-) > >Stefan/DK7FC --=====================_27043522==.ALT Content-Type: text/html; charset="us-ascii" Stefan,

did you have a look at the graph Jim (M0BMU) showed yesterday ? This may indicate that in an open area you might be better off than 1/f, maybe in the 50..100 Ohm range.
Last night I was mulling about Alexanders remark that a parallel C would increase the losses. At first though I would say that the parallel C just performs some kind of impedance transformation without inducing additional losses. And this is true if the loading coil would be perfect (no losses).
But for a real world situation (ie. assuming a constant Q = 250 for the loading coil) Alexander is right: the transformation caused by a large parallel C causes extreme high currents in the loading coil, and thus higher losses.
Simulation (with SIMetrix) confirms this.
Taking your antenna (580pF / 50 Ohm)
1. Without parallel C you would need a 550mH loading coil. At Q = 250 the coil loss would be 130 Ohm. Putting 100W into this system would result in an antenna current of about 750mA and antenna voltage of 23kV. 750mA trough the loading coil means a dissipation of 73W.
2. With a 3.2nF parallel C you would need a 85mH loading coil. At Q = 250 the coil loss would be 20 Ohm. But putting 100W into this system would result in only 330mA antenna current, while the current through the loading coil would be 2.1A (= 88W dissipation). The reduction in antenna current (750mA to 330mA) would lower the ERP by 7dB.
In addition the parallel C will decrease the antenna bandwidth significantly, making it difficult to tune.

73, Rik  ON7YD - OR7T

At 01:14 25/02/2010, you wrote:
Here i agree. And here i understand "dreamers" in a positive and optimistic way, just like children are dreamers!
We have written so many mails (including me, of course ;-) ) und could start now just to try what is possible to reach more than 10km if not done yet.

On the LF pages of DK8KW i found a notice of a successful 2 way QSO over 10km @ <9kHz. Does anybody know about more than 10km by amateurs?

Yesterday in the night i talked more than 1 hour to Markus/DF6NM and he persuaded me to try it with the 100m vertical in a first test. Maybe i get that temp licence for a 300m kite vertical but the public autoritys are still discussing if i need a special casualty insurance...

Do you, the group, think that it makes sense to try it if the next listening station is >50km or even more away? What could be possible if this would be the arrangement with the 100m vertical:
 
The wire has abt 580pF
I can get a air coil with L=85mH out of a 20kV field. DC resistance abt 150mOhm, continous current abt 30A, voltage over coil abt 30kV rms (if it remains dry(!)), measured self resonance frequency abt 50kHz.
So, if f=8,9kHz, a parallel C of abt 3,2nF is needed (i can get some 470pF/40kV Cs, no problem)
The voltage across my thin wire should be limited to abt 20kV rms, that means, antenna current should not exceed 650mA.
If Rik's 1/f dependency is valid, then my ground losses will be in the region of 250 Ohm (no houses and trees there on the hill in a radius of abt 100m; 15Ohm @ 137 kHz).
So, 100W TX power would radiate 1,4mW and thus the efficiency would be 0,0014%. In that case, i mustn't apply more than 100W since the voltage across the wire would be to high, so no need for a QRO PA...
 
If that calculation is reasonably correct, what distance could be reached with 1,4mW @ 8,9 kHz in e.g. QRSS10 and the noise level that can be expected on a sunday morning? :-)
 
73 es wish gl to all those, who are trying in these days ;-)
 
Stefan/DK7FC
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