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References: <4E418609.6020500@iup.uni-heidelberg.de> <67A6F7BF45BF4A0193A3DCB53000A283@PcMinto> <008401cc56ce$2f1fb2c0$0401a8c0@xphd97xgq27nyf> <12C475F3F4C84B818461753F2E8A60A6@PcMinto> <4E41AECB.90808@iup.uni-heidelberg.de> <8D68749D37B94275855FDBA46A3F6C97@PcMinto> <4E427DFB.50801@iup.uni-heidelberg.de> <0FA38FC9F88F41738D007D00C0B66503@PcMinto> <002e01cc5772$40601a30$0401a8c0@xphd97xgq27nyf>
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Subject: Re: LF: Re: Re: HB9ASB...
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Im sure  one  station   uses a   battery  and  radio  link  from the   =
probe  Ae   so  no  feeder  ?

G.


From: mal hamilton=20
Sent: Wednesday, August 10, 2011 4:29 PM
To: rsgb_lf_group@blacksheep.org=20
Subject: LF: Re: Re: HB9ASB...


This miniwhip/probe seems to be a very complicated antenna and difficult =
to explain its properties.=20
I suggest someone takes this antenna out into the middle of a field away =
from any noise source and work out how it actualljy performs.
because using it in a noisy environment at various heights in different =
locations introduces too many variables for accurate evaluation.
A random simple piece of wire with a suitable preamp and a counterpoise =
would probably work better.
Decca used a metal barrell probe and preamp at their RX stations maybe =
someone knows how they performed, although their sites were in a rural =
quiet environment.=20
The argument at present about this type of antenna needs to be =
concentrated on actual performance and not about environmental LOCATION, =
move it up or down a bit, use longer feed line, get it above the roof =
etc, Earth the outer braid before it enters the shack, use an isolation =
transformer.=20
Let us have your observations.
de mal/g3kev

  ----- Original Message -----=20
  From: Minto Witteveen=20
  To: rsgb_lf_group@blacksheep.org=20
  Sent: Wednesday, August 10, 2011 4:01 PM
  Subject: LF: Re: HB9ASB...


  Hi Stefan,

  Some comments:

  I think the mechanism is that the unwanted signal on the screen causes =
a=20
  potential difference between gate and source of the first (J)FET. So=20
  this causes a current flow in the output stage and so a signal at the =
RX=20
  input.

  I fail to see how that could be the main cause=E2=80=A6 because =
cutting the power to the miniwhip should then eliminate the QRM, but it =
does not! It probably attributes somewhat -  only some 10-15 dB, but =
that leaves  9+20 dB for another explanation. (i.e. my =
balanced-unbalanced hypothesis)=20

  It would almost have the same effect (when ignoring the C between =
cable=20
  and ground along to the choke near the antenna ground) as placing the=20
  choke near the antenna ground, both are in series and increase the=20
  current reducing impedance, yes...

  But I have to disagree. A choke (only) at the TX would accomplish =
nothing (in fact it may even make it worse). With a choke at the RX end =
the coax will =E2=80=93 acting as an antenna - still pick up all kinds =
of noise in the house, and this get transported via the outside of the =
coax to the miniwhip. Placing the chocke+ground near the miniwhip will =
on the other hand attenuate all the noise that is picked up along the =
coax.
  An (additional) choke at the RX end _might_ make things worse at LF =
because in that case the noise will not be bled to earth there, with the =
result that the overall noise voltage on the outside might be still =
higher.

  Hm, i rather expect a galvanic coupling i.e. stray currenty on the=20
  supply cable of the RX. What happens if you run the RX on batteries? =
The=20
  same dependency?

  Running the 817 on batteries makes no difference. And galvanic =
coupling is unlikely because the QRM completely disappears when I =
disconnect the coax in the shack=E2=80=A6. And the coax is not connected =
to anything else up to the miniwhip.=20
  As for the necessity of a current balun or common mode choke when =
going form unbalanced to balanced:  picture a classic dipole fed by =
coax. (TX) current runs through the center conductor. Kirchofs law =
states that the same current must flow in the other direction (on the =
inside of the braid). Now at the dipole the current from the center =
conductor only has one way to go: into 1 half of the dipole. But the =
current on the inside of the braid has two paths: into the second half =
of the dipole AND into the outer side of the braid. The actual =
distribution is determined by the relative impedances these two other =
halves of the dipole have at the specific frequency. Enter the choke, =
which effectively blocks the path to the outer side of the braid. The =
same mechanism is true for reception.

  Today it's nice WX here! And in NL?

  What can I say=E2=80=A6 at least it isn=E2=80=99t raining today. But =
unfortunately I have other duties (QRL)

  Overall an interesting discussion!! I am curious if there are any =
other (competing) theories J

  =20

  Regards,
  Minto pa3bca

  Hi Minto,

  Am 10.08.2011 13:10, schrieb Minto Witteveen:
  > Hi Stefan, (et al)
  >
  > Well I beg to differ.. :-)
  > What I think happens is this: The outside of the coax picks up=20
  > electromagnetic radiation like any antenna (including QRM generated =
by=20
  > fluorescent lamps and Alinco switching power supplies). This signal=20
  > travels along the coax to the Miniwhip. (also in the direction of =
the=20
  > receiver but that is not important here as the signal is on the=20
  > outside of the coax).
  > Upon arrival at the miniwhip this signal on the outside of the coax=20
  > has nowhere to go =C2=ADbut to the _inside_ of the outer mantle of =
the coax=20
  > =E2=80=93 it =E2=80=98rounds the corner=E2=80=99 at the end of the =
coax so to speak.
  I think the mechanism is that the unwanted signal on the screen causes =
a=20
  potential difference between gate and source of the first (J)FET. So=20
  this causes a current flow in the output stage and so a signal at the =
RX=20
  input.
  A common mode choke between RX and the antenna ground should form a =
low=20
  pass filter for unwanted signals coming from the shack. Using a common =

  mode choke without a local ground should have little effect, except =
the=20
  coax is some 100m long (between choke and probe) ;-)

  Ah BTW regarding the discussion "the cable to the E field probe is the =

  actual antenna": One could just try what happens if one disconnects =
the=20
  power supply. If the signal is still present then the cable is the=20
  antenna, if the signal is gone: The probe must be the antenna. Isn't=20
  it?! :-)


  > So how to avoid the QRM that is picked up by the coax to =
=E2=80=98travel back=E2=80=99=20
  > via the inside: for the miniwhip it is indeed best (as Roelof=20
  > mentioned) to short these signals to earth _outside_ the house,=20
  > preferably as close to the miniwhip as possible. Grounding there =
would=20
  > to the trick, aided by a (large enough) common mode choke between =
the=20
  > ground point and the house. The QRM that is picked up in the house=20
  > would be =E2=80=93 after attenuation by the choke - directed into =
the ground=20
  > and not up into the pole and the miniwhip.

  Yes yes, totally agreed.
  > Whatever happens in the house would then be largely irrelevant. =
Adding=20
  > a common mode choke close to the rig will do little extra. (it would =

  > only attenuate QRM getting from the shack=E2=80=99s earth system to =
the=20
  > outside of the coax).
  It would almost have the same effect (when ignoring the C between =
cable=20
  and ground along to the choke near the antenna ground) as placing the=20
  choke near the antenna ground, both are in series and increase the=20
  current reducing impedance, yes...

  > Any signals picked up by the vertical coax between the earthing =
point=20
  > and the whip will add to the received signal, but at low frequencies =

  > it will not be much.
  > So far for theory. Now the proof of the pudding: DCF39 is now > =
S9+40=20
  > dB. My old trusty QRM generator (Alinco SMPS) generates S9+25 at=20
  > 135.500. When I switch off the miniwhip (cut the power) DCF39 drops=20
  > down to just above the noise floor. As expected.
  Ah yes, that's what i meant above (should have read your mail =
completely=20
  before answering ;-) ). This is the proof that Mal cannot be right =
when=20
  saying "the coax is the actual antenna".
  > But the Alinco signal only drops down some 15 dB and remains the =
only=20
  > signal that is audible. This is exactly what I would expect: the QRM =

  > travels along the outside of the coax to the miniwhip, =
=E2=80=98rounds the=20
  > corner=E2=80=99 and comes back via the inside of the coax shield. =
Further=20
  > proof that it indeed takes this route: if I disconnect the coax in =
the=20
  > shack the Alinco smps signal disappears also (so it is not received=20
  > via any other path).
  Hm, i rather expect a galvanic coupling i.e. stray currenty on the=20
  supply cable of the RX. What happens if you run the RX on batteries? =
The=20
  same dependency?
  There could be several reasons apply here...

  > Last year I already bought 3 meters of copper pipe to drive into the =

  > ground in the backyard. Bet never got around to finish the =
job=E2=80=A6
  Today it's nice WX here! And in NL?
  >
  > The main reason the signal strength is much higher with the elevated =

  > miniwhip is (I think) caused by the fact that I am surrounded by =
other=20
  > houses, gardens, trees etc. Not comparable with an open =
field=E2=80=A6
  Yes.

  73, Stefan /DK7FC





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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML xmlns:o =3D "urn:schemas-microsoft-com:office:office"><HEAD>
<META content=3Dtext/html;charset=3Dutf-8 http-equiv=3DContent-Type>
<META name=3DGENERATOR content=3D"MSHTML 8.00.6001.19088">
<STYLE></STYLE>
</HEAD>
<BODY style=3D"PADDING-LEFT: 10px; PADDING-RIGHT: 10px; PADDING-TOP: =
15px" dir=3Dltr=20
id=3DMailContainerBody leftMargin=3D0 topMargin=3D0 bgColor=3D#ffffff=20
CanvasTabStop=3D"true" name=3D"Compose message area">
<DIV><FONT size=3D2 face=3DArial>Im sure&nbsp; one&nbsp; =
station&nbsp;&nbsp; uses=20
a&nbsp;&nbsp; battery&nbsp; and&nbsp; radio&nbsp; link&nbsp; from=20
the&nbsp;&nbsp; probe&nbsp; Ae&nbsp;&nbsp; so&nbsp; no&nbsp; =
feeder&nbsp;=20
?</FONT></DIV>
<DIV><FONT size=3D2 face=3DArial></FONT>&nbsp;</DIV>
<DIV><FONT size=3D2 face=3DArial>G.</FONT></DIV>
<DIV style=3D"FONT: 10pt Tahoma">
<DIV><BR></DIV>
<DIV style=3D"BACKGROUND: #f5f5f5">
<DIV style=3D"font-color: black"><B>From:</B> <A =
title=3Dg3kevmal@talktalk.net=20
href=3D"mailto:g3kevmal@talktalk.net">mal hamilton</A> </DIV>
<DIV><B>Sent:</B> Wednesday, August 10, 2011 4:29 PM</DIV>
<DIV><B>To:</B> <A title=3Drsgb_lf_group@blacksheep.org=20
href=3D"mailto:rsgb_lf_group@blacksheep.org">rsgb_lf_group@blacksheep.org=
</A>=20
</DIV>
<DIV><B>Subject:</B> LF: Re: Re: HB9ASB...</DIV></DIV></DIV>
<DIV><BR></DIV>
<DIV><FONT face=3DArial>This miniwhip/probe seems to be a very =
complicated antenna=20
and difficult to explain its properties. </FONT></DIV>
<DIV><FONT face=3DArial>I suggest someone takes this antenna out into =
the middle=20
of a field away from any noise source and work out how it actualljy=20
performs.</FONT></DIV>
<DIV><FONT face=3DArial>because using it in a noisy environment at =
various heights=20
in different locations introduces too many variables for accurate=20
evaluation.</FONT></DIV>
<DIV><FONT face=3DArial>A random simple&nbsp;piece of wire with a =
suitable preamp=20
and a counterpoise would probably work better.</FONT></DIV>
<DIV><FONT face=3DArial>Decca used a metal&nbsp;barrell probe and preamp =
at their=20
RX stations maybe someone knows how they performed, although their sites =
were in=20
a rural quiet environment. </FONT></DIV>
<DIV><FONT face=3DArial>The argument at present about this type of=20
antenna&nbsp;needs&nbsp;to be concentrated on actual performance and not =
about=20
environmental LOCATION, move it up or down a bit, use longer feed line, =
get it=20
above the roof etc, Earth the outer braid before it enters the =
shack,&nbsp;use=20
an isolation transformer.&nbsp;</FONT></DIV>
<DIV><FONT face=3DArial>Let us have your observations.</FONT></DIV>
<DIV><FONT face=3DArial>de mal/g3kev</FONT></DIV>
<DIV>&nbsp;</DIV>
<BLOCKQUOTE=20
style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; =
PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px"=20
dir=3Dltr>
  <DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
  <DIV=20
  style=3D"FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: =
black"><B>From:</B>=20
  <A title=3Dminto.witteveen@gmail.com=20
  href=3D"mailto:minto.witteveen@gmail.com">Minto Witteveen</A> </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Drsgb_lf_group@blacksheep.org=20
  =
href=3D"mailto:rsgb_lf_group@blacksheep.org">rsgb_lf_group@blacksheep.org=
</A>=20
  </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Wednesday, August 10, =
2011 4:01=20
  PM</DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Subject:</B> LF: Re: =
HB9ASB...</DIV>
  <DIV><BR></DIV>
  <DIV dir=3Dltr>
  <DIV style=3D"FONT-FAMILY: 'Arial'; COLOR: #000000; FONT-SIZE: 10pt">
  <DIV>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>Hi =
Stefan,<o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>Some =
comments:<o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt 0.5in" class=3DMsoNormal><I=20
  style=3D"mso-bidi-font-style: normal">I think the mechanism is that =
the unwanted=20
  signal on the screen causes a <BR>potential difference between gate =
and source=20
  of the first (J)FET. So <BR>this causes a current flow in the output =
stage and=20
  so a signal at the RX <BR>input.<o:p></o:p></I></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>I fail to see how =
that could=20
  be the main cause=E2=80=A6 because cutting the power to the miniwhip =
should then=20
  eliminate the QRM, but it does not! It probably attributes somewhat - =
<SPAN=20
  style=3D"mso-spacerun: yes">&nbsp;</SPAN>only some 10-15 dB, but that =
leaves=20
  <SPAN style=3D"mso-spacerun: yes">&nbsp;</SPAN>9+20 dB for another =
explanation.=20
  (i.e. my balanced-unbalanced hypothesis) <o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt 0.5in" class=3DMsoNormal><I=20
  style=3D"mso-bidi-font-style: normal">It would almost have the same =
effect (when=20
  ignoring the C between cable <BR>and ground along to the choke near =
the=20
  antenna ground) as placing the <BR>choke near the antenna ground, both =
are in=20
  series and increase the <BR>current reducing impedance,=20
  yes...<o:p></o:p></I></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>But I have to =
disagree. A=20
  choke (only) at the TX would accomplish nothing (in fact it may even =
make it=20
  worse). With a choke at the RX end the coax will =E2=80=93 acting as =
an antenna -=20
  still pick up all kinds of noise in the house, and this get =
transported via=20
  the outside of the coax to the miniwhip. Placing the chocke+ground =
near the=20
  miniwhip will on the other hand attenuate all the noise that is picked =
up=20
  along the coax.<BR>An (additional) choke at the RX end _might_ make =
things=20
  worse at LF because in that case the noise will not be bled to earth =
there,=20
  with the result that the overall noise voltage on the outside might be =
still=20
  higher.<o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt 0.5in" class=3DMsoNormal><I=20
  style=3D"mso-bidi-font-style: normal">Hm, i rather expect a galvanic =
coupling=20
  i.e. stray currenty on the <BR>supply cable of the RX. What happens if =
you run=20
  the RX on batteries? The <BR>same dependency?<o:p></o:p></I></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>Running the 817 on =
batteries=20
  makes no difference. And galvanic coupling is unlikely because the QRM =

  completely disappears when I disconnect the coax in the =
shack=E2=80=A6. And the coax=20
  is not connected to anything else up to the miniwhip. <BR>As for the =
necessity=20
  of a current balun or common mode choke when going form unbalanced to=20
  balanced:<SPAN style=3D"mso-spacerun: yes">&nbsp; </SPAN>picture a =
classic=20
  dipole fed by coax. (TX) current runs through the center conductor. =
Kirchofs=20
  law states that the same current must flow in the other direction (on =
the=20
  inside of the braid). Now at the dipole the current from the center =
conductor=20
  only has one way to go: into 1 half of the dipole. But the current on =
the=20
  inside of the braid has two paths: into the second half of the dipole =
AND into=20
  the outer side of the braid. The actual distribution is determined by =
the=20
  relative impedances these two other halves of the dipole have at the =
specific=20
  frequency. Enter the choke, which effectively blocks the path to the =
outer=20
  side of the braid. The same mechanism is true for =
reception.<o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt 0.5in" class=3DMsoNormal><I=20
  style=3D"mso-bidi-font-style: normal">Today it's nice WX here! And in=20
  NL?<o:p></o:p></I></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>What can I =
say=E2=80=A6 at least it=20
  isn=E2=80=99t raining today. But unfortunately I have other duties=20
(QRL)<o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>Overall an =
interesting=20
  discussion!! I am curious if there are any other (competing) theories =
<SPAN=20
  style=3D"FONT-FAMILY: wingdings; mso-ascii-font-family: calibri; =
mso-ascii-theme-font: minor-latin; mso-hansi-font-family: calibri; =
mso-hansi-theme-font: minor-latin; mso-char-type: symbol; =
mso-symbol-font-family: wingdings"><SPAN=20
  style=3D"mso-char-type: symbol; mso-symbol-font-family: =
wingdings">J</SPAN></SPAN><o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt" =
class=3DMsoNormal><o:p></o:p>&nbsp;</P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>Regards,<BR>Minto=20
  pa3bca<o:p></o:p></P>
  <P style=3D"MARGIN: 0in 0in 10pt" class=3DMsoNormal>Hi =
Minto,<BR><BR>Am 10.08.2011=20
  13:10, schrieb Minto Witteveen:<BR>&gt; Hi Stefan, (et =
al)<BR>&gt;<BR>&gt;=20
  Well I beg to differ.. :-)<BR>&gt; What I think happens is this: The =
outside=20
  of the coax picks up <BR>&gt; electromagnetic radiation like any =
antenna=20
  (including QRM generated by <BR>&gt; fluorescent lamps and Alinco =
switching=20
  power supplies). This signal <BR>&gt; travels along the coax to the =
Miniwhip.=20
  (also in the direction of the <BR>&gt; receiver but that is not =
important here=20
  as the signal is on the <BR>&gt; outside of the coax).<BR>&gt; Upon =
arrival at=20
  the miniwhip this signal on the outside of the coax <BR>&gt; has =
nowhere to go=20
  &shy;but to the _inside_ of the outer mantle of the coax <BR>&gt; =
=E2=80=93 it =E2=80=98rounds=20
  the corner=E2=80=99 at the end of the coax so to speak.<BR>I think the =
mechanism is=20
  that the unwanted signal on the screen causes a <BR>potential =
difference=20
  between gate and source of the first (J)FET. So <BR>this causes a =
current flow=20
  in the output stage and so a signal at the RX <BR>input.<BR>A common =
mode=20
  choke between RX and the antenna ground should form a low <BR>pass =
filter for=20
  unwanted signals coming from the shack. Using a common <BR>mode choke =
without=20
  a local ground should have little effect, except the <BR>coax is some =
100m=20
  long (between choke and probe) ;-)<BR><BR>Ah BTW regarding the =
discussion "the=20
  cable to the E field probe is the <BR>actual antenna": One could just =
try what=20
  happens if one disconnects the <BR>power supply. If the signal is =
still=20
  present then the cable is the <BR>antenna, if the signal is gone: The =
probe=20
  must be the antenna. Isn't <BR>it?! :-)<BR><BR><BR>&gt; So how to =
avoid the=20
  QRM that is picked up by the coax to =E2=80=98travel back=E2=80=99 =
<BR>&gt; via the inside:=20
  for the miniwhip it is indeed best (as Roelof <BR>&gt; mentioned) to =
short=20
  these signals to earth _outside_ the house, <BR>&gt; preferably as =
close to=20
  the miniwhip as possible. Grounding there would <BR>&gt; to the trick, =
aided=20
  by a (large enough) common mode choke between the <BR>&gt; ground =
point and=20
  the house. The QRM that is picked up in the house <BR>&gt; would be =
=E2=80=93 after=20
  attenuation by the choke - directed into the ground <BR>&gt; and not =
up into=20
  the pole and the miniwhip.<BR><BR>Yes yes, totally agreed.<BR>&gt; =
Whatever=20
  happens in the house would then be largely irrelevant. Adding <BR>&gt; =
a=20
  common mode choke close to the rig will do little extra. (it would =
<BR>&gt;=20
  only attenuate QRM getting from the shack=E2=80=99s earth system to =
the <BR>&gt;=20
  outside of the coax).<BR>It would almost have the same effect (when =
ignoring=20
  the C between cable <BR>and ground along to the choke near the antenna =
ground)=20
  as placing the <BR>choke near the antenna ground, both are in series =
and=20
  increase the <BR>current reducing impedance, yes...<BR><BR>&gt; Any =
signals=20
  picked up by the vertical coax between the earthing point <BR>&gt; and =
the=20
  whip will add to the received signal, but at low frequencies <BR>&gt; =
it will=20
  not be much.<BR>&gt; So far for theory. Now the proof of the pudding: =
DCF39 is=20
  now &gt; S9+40 <BR>&gt; dB. My old trusty QRM generator (Alinco SMPS)=20
  generates S9+25 at <BR>&gt; 135.500. When I switch off the miniwhip =
(cut the=20
  power) DCF39 drops <BR>&gt; down to just above the noise floor. As=20
  expected.<BR>Ah yes, that's what i meant above (should have read your =
mail=20
  completely <BR>before answering ;-) ). This is the proof that Mal =
cannot be=20
  right when <BR>saying "the coax is the actual antenna".<BR>&gt; But =
the Alinco=20
  signal only drops down some 15 dB and remains the only <BR>&gt; signal =
that is=20
  audible. This is exactly what I would expect: the QRM <BR>&gt; travels =
along=20
  the outside of the coax to the miniwhip, =E2=80=98rounds the <BR>&gt; =
corner=E2=80=99 and=20
  comes back via the inside of the coax shield. Further <BR>&gt; proof =
that it=20
  indeed takes this route: if I disconnect the coax in the <BR>&gt; =
shack the=20
  Alinco smps signal disappears also (so it is not received <BR>&gt; via =
any=20
  other path).<BR>Hm, i rather expect a galvanic coupling i.e. stray =
currenty on=20
  the <BR>supply cable of the RX. What happens if you run the RX on =
batteries?=20
  The <BR>same dependency?<BR>There could be several reasons apply=20
  here...<BR><BR>&gt; Last year I already bought 3 meters of copper pipe =
to=20
  drive into the <BR>&gt; ground in the backyard. Bet never got around =
to finish=20
  the job=E2=80=A6<BR>Today it's nice WX here! And in =
NL?<BR>&gt;<BR>&gt; The main=20
  reason the signal strength is much higher with the elevated <BR>&gt; =
miniwhip=20
  is (I think) caused by the fact that I am surrounded by other <BR>&gt; =
houses,=20
  gardens, trees etc. Not comparable with an open =
field=E2=80=A6<BR>Yes.<BR><BR>73,=20
  Stefan /DK7FC<BR><BR style=3D"mso-special-character: line-break"><BR=20
  style=3D"mso-special-character: =
line-break"><o:p></o:p></P></DIV></DIV></DIV></BLOCKQUOTE>
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