Envelope-to: dave@picks.force9.co.uk Delivery-date: Wed, 01 Feb 2006 15:54:48 +0000 Received: by ptb-mxcore02.plus.net with spam-scanned (PlusNet MXCore v2.00) id 1F4KJi-0001UH-9w for dave@picks.force9.co.uk; Wed, 01 Feb 2006 15:54:47 +0000 Received: from post.thorcom.com ([193.82.116.20]) by ptb-mxcore02.plus.net with esmtp (PlusNet MXCore v2.00) id 1F4KJi-0001RC-5P for dave@picks.force9.co.uk; Wed, 01 Feb 2006 15:54:46 +0000 Received: from majordom by post.thorcom.com with local (Exim 4.14) id 1F4KJA-0002T9-Ju for rs_out_1@blacksheep.org; Wed, 01 Feb 2006 15:54:12 +0000 Received: from [193.82.116.32] (helo=relay1.thorcom.net) by post.thorcom.com with esmtp (Exim 4.14) id 1F4KJA-0002T0-6X for rsgb_lf_group@blacksheep.org; Wed, 01 Feb 2006 15:54:12 +0000 Received: from newbox.tcp.net.uk ([195.80.0.243]) by relay1.thorcom.net with esmtp (Exim 4.51) id 1F4Lcl-0002oB-FO for rsgb_lf_group@blacksheep.org; Wed, 01 Feb 2006 17:18:49 +0000 Received: from standalone ([212.248.140.26]) by newbox.tcp.net.uk (8.12.7/8.12.7) with SMTP id k11FrKoT000223 for ; Wed, 1 Feb 2006 15:53:22 GMT Message-ID: <002901c62746$fc8ed190$1a8cf8d4@standalone> From: "Andy" To: rsgb_lf_group@blacksheep.org Date: Wed, 1 Feb 2006 15:48:43 -0000 MIME-Version: 1.0 X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 4.72.3110.5 X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 X-TCP-MailScanner-Information: Please visit www.tcp.co.uk for more information X-TCP-MailScanner: Found to be clean X-TCP-MailScanner-SpamScore: s X-TCP-MailScanner-From: actalbot@southsurf.com Subject: Re: LF: Can't see the wood for the trees Content-Type: text/plain; charset=iso-8859-1; format=flowed Content-Transfer-Encoding: 8bit X-SA-Exim-Scanned: Yes Sender: owner-rsgb_lf_group@blacksheep.org Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group X-SA-Exim-Rcpt-To: rs_out_1@blacksheep.org X-SA-Exim-Scanned: No; SAEximRunCond expanded to false X-PN-SpamFiltered: by PlusNet MXCore (v2.00) Yes - that's the obvious bit I was missing - go back to first principles and do the actual Fourier transform on the waveform. There ought to be a short cut, though, knowing the integral is finite and contains total power in the signal. I had assumed the Dirichlet integral converged, but didn't know the result, so maybe that is the way to go. Tnx Andy G4JNT www.scrbg.org/g4jnt/ -----Original Message----- From: Warren K2ORS/WD2XGJ To: rsgb_lf_group@blacksheep.org ; rsgb_lf_group@blacksheep.org Cc: Andy Date: 2006/02/01 15:34 Subject: Re: LF: Can't see the wood for the trees >Andy, > > Unless I'm missing the meaning of your question, I believe you want the fourier coefficients to determine the amplitudes of the components making up the pulse train. Also, should you feel the need to integrate sin(x)/x, the so-called Dirichlet integral, it does converge and the definite integral from 0 to infinity of sin(x)/x = pi/2. For reference see: >http://www.pupress.princeton.edu/books/maor/chapter_10.pdf > > I'm in the middle of a project at the moment but let me know if I'm on the right track - I could help with the fourier coefficients perhaps this evening. > >-- >73 Warren K2ORS/WD2XGJ >FN42hi >http://www.w4dex.com/wd2xgj.htm > > -------------- Original message ---------------------- >From: "Andy" >> Can someone help with what should be obvious. >> >> I have a train of constant width pulses at a fixed repetition rate. In the >> frequency domain these appear as a spectral comb with spacing at the >> repetition rate, whose amplitude follows a SIN(X) / X shape depending on >> the pulse width, ie. the first null occuring at at 1/width and so on. >> >> What I'm getting tied up in knots trying to calculate is : >> >> What is the absolute amplitude (power) of just one individual tooth of the >> comb at any particular spacing. >> >> Assume the pulse waveform has, say, 1mW or 0dBm mean amplitude, and >> consists of 500us pulses at 40Hz PRI. The duty cycle is 0.02, so the >> individual pulse power would have to be 50mW or 17dBm to get this mean. >> But what is the amplitude of the component at, say, 1kHz, or 1040Hz, or >> 10kHz ?? >> >> It must be obvious, but I keep feeling the urge to integrate SIN(X) / X >> which is not funny and way beyond my maths capabilities!! >> >> The figures given above are those for the 5MHz beacon sounder sequence. >> The amplitude trace on the monitoring software during the sounder sequence >> is measuring just one line of the comb ( F = 0, the carrier) , and appears >> to suggest this is about 30 - 35dB down on the CW part. That is -17dB from >> the peak/mean as above, but where does the other 13 - 18dB come from? >> >> Tearing hair out >> >> Andy G4JNT >> www.scrbg.org/g4jnt/ >> >> >> > > >