Return-Path: Received: (qmail 4895 invoked from network); 29 Oct 2001 23:27:05 -0000 Received: from unknown (HELO murphys-inbound.services.quay.plus.net) (212.159.14.225) by excalibur.plus.net with SMTP; 29 Oct 2001 23:27:05 -0000 Received: (qmail 15946 invoked from network); 29 Oct 2001 23:25:40 -0000 Received: from unknown (HELO post.thorcom.com) (212.172.148.70) by murphys.services.quay.plus.net with SMTP; 29 Oct 2001 23:25:40 -0000 Received: from majordom by post.thorcom.com with local (Exim 3.33 #2) id 15yLio-0000Aj-00 for rsgb_lf_group-outgoing@blacksheep.org; Mon, 29 Oct 2001 23:21:34 +0000 Received: from chalfont.mail.uk.easynet.net ([212.135.1.67]) by post.thorcom.com with esmtp (Exim 3.33 #2) id 15yLin-0000Ae-00 for rsgb_lf_group@blacksheep.org; Mon, 29 Oct 2001 23:21:33 +0000 Received: from ericadodd (tnt-6-8.easynet.co.uk [195.40.201.8]) by chalfont.mail.uk.easynet.net (Postfix) with SMTP id 87D8B1D59C9 for ; Mon, 29 Oct 2001 23:20:52 +0000 (GMT) Message-ID: <002501c160d0$873758e0$a1ca28c3@ericadodd> From: "g3ldo" To: rsgb_lf_group@blacksheep.org References: <2614258.1004295195891.JavaMail.computernetworks@gomailjtp05> <3.0.1.16.20011029161314.30eff79c@mail.cc.kuleuven.ac.be> Subject: Re: LF: Decca Coils Date: Mon, 29 Oct 2001 23:21:22 -0000 MIME-Version: 1.0 Content-Type: text/plain; charset=iso-8859-1; format=flowed Content-Transfer-Encoding: 8bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.50.4522.1200 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Sender: Hi Rik > L = inductance (nH) > N = windings > D = average coil diameter (cm) > H = coil length (cm) > C = thickness of the wirelayers (all together, in cm) > K = correction factor depending on H/C ratio : > L/C K > 2 0.10 > 3 0.15 > 5 0.23 > 10 0.27 > 15 0.30 > 20 0.31 > 30 0.32 > > 2. For 'fat' coils (H<=D) : L = 78*L^2*D/(3*D+9*H+10*C) I will use the 'fat' coil formula because with my coil D = 60cm and H = 18.2cm I don't understand the L^2 in the formula because L is what I am trying to find. Regards, Peter, G3LDO e-mail Web