Envelope-to: dave@picks.force9.co.uk Delivery-date: Wed, 01 Feb 2006 16:12:07 +0000 Received: by ptb-mxcore02.plus.net with spam-scanned (PlusNet MXCore v2.00) id 1F4KaT-0005ro-2x for dave@picks.force9.co.uk; Wed, 01 Feb 2006 16:12:07 +0000 Received: from post.thorcom.com ([193.82.116.20]) by ptb-mxcore02.plus.net with esmtp (PlusNet MXCore v2.00) id 1F4KaS-0005mn-99 for dave@picks.force9.co.uk; Wed, 01 Feb 2006 16:12:04 +0000 Received: from majordom by post.thorcom.com with local (Exim 4.14) id 1F4Ka9-00030m-W6 for rs_out_1@blacksheep.org; Wed, 01 Feb 2006 16:11:45 +0000 Received: from [193.82.116.32] (helo=relay1.thorcom.net) by post.thorcom.com with esmtp (Exim 4.14) id 1F4Ka9-00030d-K1 for rsgb_lf_group@blacksheep.org; Wed, 01 Feb 2006 16:11:45 +0000 Received: from smtp811.mail.ukl.yahoo.com ([217.12.12.201]) by relay1.thorcom.net with smtp (Exim 4.51) id 1F4Ltk-00032D-8X for rsgb_lf_group@blacksheep.org; Wed, 01 Feb 2006 17:36:23 +0000 Received: (qmail 22893 invoked from network); 1 Feb 2006 16:10:25 -0000 Received: from unknown (HELO lark) (alan.melia@btinternet.com@81.131.133.127 with login) by smtp811.mail.ukl.yahoo.com with SMTP; 1 Feb 2006 16:10:24 -0000 Message-ID: <001501c6274a$04bb8860$67b0fea9@lark> From: "Alan Melia" To: rsgb_lf_group@blacksheep.org References: <000e01c6273f$7b8710f0$018cf8d4@standalone> Date: Wed, 1 Feb 2006 16:09:53 -0000 MIME-Version: 1.0 X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.00.2615.200 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2615.200 Subject: LF: Re: Can't see the wood for the trees Content-Type: text/plain; charset=Windows-1252; format=flowed Content-Transfer-Encoding: 8bit X-SA-Exim-Scanned: Yes Sender: owner-rsgb_lf_group@blacksheep.org Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group X-SA-Exim-Rcpt-To: rs_out_1@blacksheep.org X-SA-Exim-Scanned: No; SAEximRunCond expanded to false X-PN-SpamFiltered: by PlusNet MXCore (v2.00) Hi Andy I think what you are looking for is given on page 22 of my copy of "Radio Engineers Handbook" by Terman I am sure you have access to a copy if not I could scan Cheers de Alan G3NYK ----- Original Message ----- From: Andy To: Sent: 01 February 2006 14:51 Subject: LF: Can't see the wood for the trees > Can someone help with what should be obvious. > > I have a train of constant width pulses at a fixed repetition rate. In the > frequency domain these appear as a spectral comb with spacing at the > repetition rate, whose amplitude follows a SIN(X) / X shape depending on > the pulse width, ie. the first null occuring at at 1/width and so on. > > What I'm getting tied up in knots trying to calculate is : > > What is the absolute amplitude (power) of just one individual tooth of the > comb at any particular spacing. > > Assume the pulse waveform has, say, 1mW or 0dBm mean amplitude, and > consists of 500us pulses at 40Hz PRI. The duty cycle is 0.02, so the > individual pulse power would have to be 50mW or 17dBm to get this mean. > But what is the amplitude of the component at, say, 1kHz, or 1040Hz, or > 10kHz ?? > > It must be obvious, but I keep feeling the urge to integrate SIN(X) / X > which is not funny and way beyond my maths capabilities!! > > The figures given above are those for the 5MHz beacon sounder sequence. > The amplitude trace on the monitoring software during the sounder sequence > is measuring just one line of the comb ( F = 0, the carrier) , and appears > to suggest this is about 30 - 35dB down on the CW part. That is -17dB from > the peak/mean as above, but where does the other 13 - 18dB come from? > > Tearing hair out > > Andy G4JNT > www.scrbg.org/g4jnt/ > > >